OBJECTIVE ANSWERS
Verified Maths OBJ
1-10: cbdccdbbcd
11-20: caacabacdd
21-30: ddaccbacda
31-40: bbcddaacdc
41-50: abbabbccab
(1a)
(27/8)+(13/8)=(40/8) ,
3/4*5/1=15/4,
17/8-3/2=5/8,
(15/4)/(5/8)=15/4*8/5 =6
(1b.) log 1.125=log
1125/1000 =log9/8,
log10 rtp 9/8=log10rtp9-
log10rtp8=log10rtp3rtp2-
log10rtp2rtp3 ,
2log10rtp3-3log10rtp2
=2*04771
-3*0.3010=0.0512.
PLS NOTE THAT rtp means
Raise to Power.
And * means multiply.
(2a)
7x+4< 1/2(4x+3) =(7x+4)/1 < (4x+ 3)/2 =2(7x+4) < (4x+3) = 14x+8 < 4x+3 =14x-4x < 3-8 =10x/10 < -5/10 =x< -1/2 = x>-1/2
(2b)
Sale,,sunday,shaka=1100
There various ratio= 3:2:1
=6
Thaka's share: 1/6*1100 =
183.33 naira
(3b)
(x+y+z)/3 =6 -------(eqn
1)
(x+y+z+t+u+v+w)/7 =9
----(eqn 2)
(t+u+v+w)/4=?
(9*7) - (6*3)
63-18 = 45
45/4=11.3
t,u,v,w= 11.3
(6ai) If P>Q, and P+Q=3(p-
q) -> p+q=3p-3q,
P+q=3p-3p,
3q+q=3p-p,
4q=2p,
4q/2=2p/2 => p=2q
(6aii)Evaluate p2 +q2/pq=
(2q)2+q2/(2q)(q),
=>4q2+q2/2p2=5q2/2q2=5/2
(6b)selling price(sp)=25 at #
66 of 100 pieces.
=>(25*#66)*4=#
6600/25=264 (% profit)=32%
,
if at 2o for #50,
=>(20*50)*5/20,
=>#250
.: %profit=profit/c.p*100,
32=profit/c.p*100,
32=s.p-c.p/c.p*100,
32=100=264-c.p/c.p,
32cp=26400-100cp
C.p=cost price,
At 20 for #50.
=s.p-c.p=#250-#200=#50.
%gain=s.p-c.p*100,
%gain=#50/#200*100=25/4.
(13a)
draw the diagram of a lader
against the wall
|_\
(13b)
sin37=5/x
x=5/sin37
x=5/0.6018
x=8.31metre
(13c)
we av to first get the
distance of ladder frm the
ground ising sohcahtoa
8.31^2=y^2+5^2
y=sqr rut (8.31^2-5^2)
y=sqr rut(69.06-25)
=sqr rut (44.6)=6.63
if the ladder is moved 2m
then y-2
=6.63-2
=4..63
using sohcahtoa
cos x=4.63/8.31
x=cos^-1(0.5571)
x=54.75 degree.
(10a)
r=3/2l
l=2rsin tita/2
p:-perimeter of rectangle- periemeter of semi
circle
p of rectangle =
2(12+220
P:-pIE R+ pie*(3/2)*2sin (tita/2)
tita=39 degree
perimeter of semi circle=
22/7*(7)
perimeter of entire shape=
22+12+12+5+3+22
=76CM
(10b)
3/(sqr rut 3)(2/(sqr rut 3)-(sqr rut 12)/6)
6/3-1/2(sqr rut 12/ sqr rut 3)
2-1/2*sqr rut4= 2-2/2=
=1
(8a)
(3-x),6,(7-5x)
g.p. r70
6/3-x=7-5x/6
36=(3-x)(7-5x)
36=(3-x)(7-5x)
36=21-15x-7x+5x ^2
36=21-22x+5x^2
5x^2-22x-15=0
x(5x+3)-5(5x+3) =0
(x-5)(5x+3)=0
x=5 or x=5/3
x=5 or -5/3
NOTE:
^ Means Raise to power.
(8b)
Draw a trapezium with ABCD
ADC=tita
sin tita=3/6
sin^-1(1/2)=0.5
tita=sin^(-1)= 30degree
(5a)
draw diagram
(5b)
6^2 + 3^2 =L^2
36+9=L^2
L:sqrt(45)= 6.7m
tita = tan tita=3/6
tan (tita)=0.5
tita= tan^-1 0.5
tita= 26.57 degree.
Verified Maths OBJ
1-10: cbdccdbbcd
11-20: caacabacdd
21-30: ddaccbacda
31-40: bbcddaacdc
41-50: abbabbccab
(1a)
(27/8)+(13/8)=(40/8) ,
3/4*5/1=15/4,
17/8-3/2=5/8,
(15/4)/(5/8)=15/4*8/5 =6
(1b.) log 1.125=log
1125/1000 =log9/8,
log10 rtp 9/8=log10rtp9-
log10rtp8=log10rtp3rtp2-
log10rtp2rtp3 ,
2log10rtp3-3log10rtp2
=2*04771
-3*0.3010=0.0512.
PLS NOTE THAT rtp means
Raise to Power.
And * means multiply.
(2a)
7x+4< 1/2(4x+3) =(7x+4)/1 < (4x+ 3)/2 =2(7x+4) < (4x+3) = 14x+8 < 4x+3 =14x-4x < 3-8 =10x/10 < -5/10 =x< -1/2 = x>-1/2
(2b)
Sale,,sunday,shaka=1100
There various ratio= 3:2:1
=6
Thaka's share: 1/6*1100 =
183.33 naira
(3b)
(x+y+z)/3 =6 -------(eqn
1)
(x+y+z+t+u+v+w)/7 =9
----(eqn 2)
(t+u+v+w)/4=?
(9*7) - (6*3)
63-18 = 45
45/4=11.3
t,u,v,w= 11.3
(6ai) If P>Q, and P+Q=3(p-
q) -> p+q=3p-3q,
P+q=3p-3p,
3q+q=3p-p,
4q=2p,
4q/2=2p/2 => p=2q
(6aii)Evaluate p2 +q2/pq=
(2q)2+q2/(2q)(q),
=>4q2+q2/2p2=5q2/2q2=5/2
(6b)selling price(sp)=25 at #
66 of 100 pieces.
=>(25*#66)*4=#
6600/25=264 (% profit)=32%
,
if at 2o for #50,
=>(20*50)*5/20,
=>#250
.: %profit=profit/c.p*100,
32=profit/c.p*100,
32=s.p-c.p/c.p*100,
32=100=264-c.p/c.p,
32cp=26400-100cp
C.p=cost price,
At 20 for #50.
=s.p-c.p=#250-#200=#50.
%gain=s.p-c.p*100,
%gain=#50/#200*100=25/4.
(13a)
draw the diagram of a lader
against the wall
|_\
(13b)
sin37=5/x
x=5/sin37
x=5/0.6018
x=8.31metre
(13c)
we av to first get the
distance of ladder frm the
ground ising sohcahtoa
8.31^2=y^2+5^2
y=sqr rut (8.31^2-5^2)
y=sqr rut(69.06-25)
=sqr rut (44.6)=6.63
if the ladder is moved 2m
then y-2
=6.63-2
=4..63
using sohcahtoa
cos x=4.63/8.31
x=cos^-1(0.5571)
x=54.75 degree.
(10a)
r=3/2l
l=2rsin tita/2
p:-perimeter of rectangle- periemeter of semi
circle
p of rectangle =
2(12+220
P:-pIE R+ pie*(3/2)*2sin (tita/2)
tita=39 degree
perimeter of semi circle=
22/7*(7)
perimeter of entire shape=
22+12+12+5+3+22
=76CM
(10b)
3/(sqr rut 3)(2/(sqr rut 3)-(sqr rut 12)/6)
6/3-1/2(sqr rut 12/ sqr rut 3)
2-1/2*sqr rut4= 2-2/2=
=1
(8a)
(3-x),6,(7-5x)
g.p. r70
6/3-x=7-5x/6
36=(3-x)(7-5x)
36=(3-x)(7-5x)
36=21-15x-7x+5x ^2
36=21-22x+5x^2
5x^2-22x-15=0
x(5x+3)-5(5x+3) =0
(x-5)(5x+3)=0
x=5 or x=5/3
x=5 or -5/3
NOTE:
^ Means Raise to power.
(8b)
Draw a trapezium with ABCD
ADC=tita
sin tita=3/6
sin^-1(1/2)=0.5
tita=sin^(-1)= 30degree
(5a)
draw diagram
(5b)
6^2 + 3^2 =L^2
36+9=L^2
L:sqrt(45)= 6.7m
tita = tan tita=3/6
tan (tita)=0.5
tita= tan^-1 0.5
tita= 26.57 degree.
0 comments:
Post a Comment